(2k+4)+(k-3)=0

Solution for (2k+4)+(k-3)=0 equation:

Simplifying
(2k + 4) + (k + -3) = 0

Reorder the terms:
(4 + 2k) + (k + -3) = 0

Remove parenthesis around (4 + 2k)
4 + 2k + (k + -3) = 0

Reorder the terms:
4 + 2k + (-3 + k) = 0

Remove parenthesis around (-3 + k)
4 + 2k + -3 + k = 0

Reorder the terms:
4 + -3 + 2k + k = 0

Combine like terms: 4 + -3 = 1
1 + 2k + k = 0

Combine like terms: 2k + k = 3k
1 + 3k = 0

Solving
1 + 3k = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3k = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3k = 0 + -1
3k = 0 + -1

Combine like terms: 0 + -1 = -1
3k = -1

Divide each side by '3'.
k = -0.3333333333

Simplifying
k = -0.3333333333