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(2k+5)/5+9=-(k-3)
We move all terms to the left:
(2k+5)/5+9-(-(k-3))=0
We multiply all the terms by the denominator
(2k+5)-((-(k-3)))*5+9*5=0
We add all the numbers together, and all the variables
(2k+5)-((-(k-3)))*5+45=0
We get rid of parentheses
2k-((-(k-3)))*5+5+45=0
We add all the numbers together, and all the variables
2k-((-(k-3)))*5+50=0
We move all terms containing k to the left, all other terms to the right
2k-((-(k-3)))*5=-50
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