(2k-10)+(4k+16)=180

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Solution for (2k-10)+(4k+16)=180 equation: 



(2k-10)+(4k+16)=180

We move all terms to the left:

(2k-10)+(4k+16)-(180)=0

We get rid of parentheses

2k+4k-10+16-180=0

We add all the numbers together, and all the variables

6k-174=0

We move all terms containing k to the left, all other terms to the right

6k=174

k=174/6

k=29

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