(2k-10)+3k=k+6

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Solution for (2k-10)+3k=k+6 equation: 



(2k-10)+3k=k+6

We move all terms to the left:

(2k-10)+3k-(k+6)=0

We add all the numbers together, and all the variables

3k+(2k-10)-(k+6)=0

We get rid of parentheses

3k+2k-k-10-6=0

We add all the numbers together, and all the variables

4k-16=0

We move all terms containing k to the left, all other terms to the right

4k=16

k=16/4

k=4

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