(2k-3)+1=8k-11

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Solution for (2k-3)+1=8k-11 equation:



(2k-3)+1=8k-11
We move all terms to the left:
(2k-3)+1-(8k-11)=0
We get rid of parentheses
2k-8k-3+11+1=0
We add all the numbers together, and all the variables
-6k+9=0
We move all terms containing k to the left, all other terms to the right
-6k=-9
k=-9/-6
k=1+1/2

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