(2k-3)/(k+9)=3/5

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Solution for (2k-3)/(k+9)=3/5 equation: 



(2k-3)/(k+9)=3/5

We move all terms to the left:

(2k-3)/(k+9)-(3/5)=0



Domain of the equation: (k+9)!=0

We move all terms containing k to the left, all other terms to the right

k!=-9

k∈R



We add all the numbers together, and all the variables

(2k-3)/(k+9)-(+3/5)=0

We get rid of parentheses

(2k-3)/(k+9)-3/5=0

We calculate fractions


(10k-15)/(5k+45)+(-3k-27)/(5k+45)=0

We multiply all the terms by the denominator


(10k-15)+(-3k-27)=0

We get rid of parentheses

10k-3k-15-27=0

We add all the numbers together, and all the variables

7k-42=0

We move all terms containing k to the left, all other terms to the right

7k=42

k=42/7

k=6

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