(2k-3)/5=7

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Solution for (2k-3)/5=7 equation: 


k in (-oo:+oo)

(2*k-3)/5 = 7 // - 7

(2*k-3)/5-7 = 0

(2*k-3)/5+(-7*5)/5 = 0

2*k-7*5-3 = 0

2*k-38 = 0

(2*k-38)/5 = 0

(2*k-38)/5 = 0 // * 5

2*k-38 = 0

2*k-38 = 0 // + 38

2*k = 38 // : 2

k = 38/2

k = 19

k = 19

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