(2m)/(m-3)=(6)/(m-3)+4

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Solution for (2m)/(m-3)=(6)/(m-3)+4 equation: 


D( m )

m-3 = 0

m-3 = 0

m-3 = 0

m-3 = 0 // + 3

m = 3

m in (-oo:3) U (3:+oo)

(2*m)/(m-3) = 6/(m-3)+4 // - 6/(m-3)+4

(2*m)/(m-3)-(6/(m-3))-4 = 0

(2*m)/(m-3)-6*(m-3)^-1-4 = 0

(2*m)/(m-3)-6/(m-3)-4 = 0

(2*m)/(m-3)-6/(m-3)+(-4*(m-3))/(m-3) = 0

2*m-4*(m-3)-6 = 0

2*m-4*m-6+12 = 0

6-2*m = 0

(6-2*m)/(m-3) = 0

(6-2*m)/(m-3) = 0 // * m-3

6-2*m = 0

6-2*m = 0 // - 6

-2*m = -6 // : -2

m = -6/(-2)

m = 3

m in { 3} 

m belongs to the empty set

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