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(2m)/5=(1/3)(2m-12)
We move all terms to the left:
(2m)/5-((1/3)(2m-12))=0
Domain of the equation: 3)(2m-12))!=0We add all the numbers together, and all the variables
m∈R
2m/5-((+1/3)(2m-12))=0
We multiply parentheses ..
-((+2m^2+1/3*-12))+2m/5=0
We calculate fractions
(-((+2m^2+1*5)/()+6m^2/()=0
We calculate terms in parentheses: +(-((+2m^2+1*5)/()+6m^2/(), so:
-((+2m^2+1*5)/()+6m^2/(
We can not solve this equation
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