(2m)/5=(1/3)(2m-12)

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Solution for (2m)/5=(1/3)(2m-12) equation: 



(2m)/5=(1/3)(2m-12)

We move all terms to the left:

(2m)/5-((1/3)(2m-12))=0



Domain of the equation: 3)(2m-12))!=0

m∈R



We add all the numbers together, and all the variables

2m/5-((+1/3)(2m-12))=0

We multiply parentheses ..

-((+2m^2+1/3*-12))+2m/5=0

We calculate fractions


(-((+2m^2+1*5)/()+6m^2/()=0



We calculate terms in parentheses: +(-((+2m^2+1*5)/()+6m^2/(), so:

-((+2m^2+1*5)/()+6m^2/(

We can not solve this equation

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