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(2m+1)(m-3)=-7
We move all terms to the left:
(2m+1)(m-3)-(-7)=0
We add all the numbers together, and all the variables
(2m+1)(m-3)+7=0
We multiply parentheses ..
(+2m^2-6m+m-3)+7=0
We get rid of parentheses
2m^2-6m+m-3+7=0
We add all the numbers together, and all the variables
2m^2-5m+4=0
a = 2; b = -5; c = +4;
Δ = b2-4ac
Δ = -52-4·2·4
Δ = -7
Delta is less than zero, so there is no solution for the equation
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