(2m+1)/7=(3m-5)/4

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Solution for (2m+1)/7=(3m-5)/4 equation: 



(2m+1)/7=(3m-5)/4

We move all terms to the left:

(2m+1)/7-((3m-5)/4)=0

We calculate fractions


2m/()+(-((3m-5)*7)/()=0



We calculate terms in parentheses: +(-((3m-5)*7)/(), so:

-((3m-5)*7)/(

We multiply all the terms by the denominator


-((3m-5)*7)



We calculate terms in parentheses: -((3m-5)*7), so:

(3m-5)*7

We multiply parentheses

21m-35

Back to the equation:

-(21m-35)



We get rid of parentheses

-21m+35

Back to the equation:

+(-21m+35)



We get rid of parentheses

2m/()-21m+35=0

We multiply all the terms by the denominator


2m-21m*()+35*()=0

We add all the numbers together, and all the variables

2m-21m*()=0

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