(2m+3/2m+5-m-1/m-2)=0

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Solution for (2m+3/2m+5-m-1/m-2)=0 equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

2*m+(3/2)*m-m-(1/m)-2+5 = 0

2*m+(3/2)*m-m-m^-1-2+5 = 0

5/2*m^1-1*m^-1+3*m^0 = 0

(5/2*m^2+3*m^1-1*m^0)/(m^1) = 0 // * m^2

m^1*(5/2*m^2+3*m^1-1*m^0) = 0

m^1

(5/2)*m^2+3*m-1 = 0

(5/2)*m^2+3*m-1 = 0

DELTA = 3^2-(-1*4*(5/2))

DELTA = 19

DELTA > 0

m = (19^(1/2)-3)/(2*(5/2)) or m = (-19^(1/2)-3)/(2*(5/2))

m = (19^(1/2)-3)/5 or m = (-(19^(1/2)+3))/5

m in { (-(19^(1/2)+3))/5, (19^(1/2)-3)/5} 

m in { (-(19^(1/2)+3))/5, (19^(1/2)-3)/5 }

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