(2m-1)19=(m)10

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Solution for (2m-1)19=(m)10 equation: 



(2m-1)19=(m)10

We move all terms to the left:

(2m-1)19-((m)10)=0

determiningTheFunctionDomain
(2m-1)19-m10=0

We add all the numbers together, and all the variables

-1m^10+(2m-1)19=0

We multiply parentheses

-1m^10+38m-19=0

We do not support empression: m^10

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