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(2m-2)(2m-2)+3(m-2)-m=0
We add all the numbers together, and all the variables
-1m+(2m-2)(2m-2)+3(m-2)=0
We multiply parentheses
-1m+(2m-2)(2m-2)+3m-6=0
We multiply parentheses ..
(+4m^2-4m-4m+4)-1m+3m-6=0
We add all the numbers together, and all the variables
(+4m^2-4m-4m+4)+2m-6=0
We get rid of parentheses
4m^2-4m-4m+2m+4-6=0
We add all the numbers together, and all the variables
4m^2-6m-2=0
a = 4; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·4·(-2)
Δ = 68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{68}=\sqrt{4*17}=\sqrt{4}*\sqrt{17}=2\sqrt{17}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{17}}{2*4}=\frac{6-2\sqrt{17}}{8} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{17}}{2*4}=\frac{6+2\sqrt{17}}{8} $
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