(2m-2)(4m-8)=0

Solution for (2m-2)(4m-8)=0 equation:

(2m-2)(4m-8)=0

We multiply parentheses ..

(+8m^2-16m-8m+16)=0

We get rid of parentheses

8m^2-16m-8m+16=0

We add all the numbers together, and all the variables

8m^2-24m+16=0

a = 8; b = -24; c = +16;
Δ = b2-4ac
Δ = -242-4·8·16
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8}{2*8}=\frac{16}{16}
=1
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8}{2*8}=\frac{32}{16}
=2
$