(2m-5)3m=0

Solution for (2m-5)3m=0 equation:

(2m-5)3m=0

We multiply parentheses

6m^2-15m=0

a = 6; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·6·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*6}=\frac{0}{12}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*6}=\frac{30}{12}
=2+1/2
$