(2n+1)(2n-1)(n+5)=

Solution for (2n+1)(2n-1)(n+5)= equation:

Simplifying
(2n + 1)(2n + -1)(n + 5) = 0

Reorder the terms:
(1 + 2n)(2n + -1)(n + 5) = 0

Reorder the terms:
(1 + 2n)(-1 + 2n)(n + 5) = 0

Reorder the terms:
(1 + 2n)(-1 + 2n)(5 + n) = 0

Multiply (1 + 2n) * (-1 + 2n)
(1(-1 + 2n) + 2n * (-1 + 2n))(5 + n) = 0
((-1 * 1 + 2n * 1) + 2n * (-1 + 2n))(5 + n) = 0
((-1 + 2n) + 2n * (-1 + 2n))(5 + n) = 0
(-1 + 2n + (-1 * 2n + 2n * 2n))(5 + n) = 0
(-1 + 2n + (-2n + 4n2))(5 + n) = 0

Combine like terms: 2n + -2n = 0
(-1 + 0 + 4n2)(5 + n) = 0
(-1 + 4n2)(5 + n) = 0

Multiply (-1 + 4n2) * (5 + n)
(-1(5 + n) + 4n2 * (5 + n)) = 0
((5 * -1 + n * -1) + 4n2 * (5 + n)) = 0
((-5 + -1n) + 4n2 * (5 + n)) = 0
(-5 + -1n + (5 * 4n2 + n * 4n2)) = 0
(-5 + -1n + (20n2 + 4n3)) = 0
(-5 + -1n + 20n2 + 4n3) = 0

Solving
-5 + -1n + 20n2 + 4n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.