(2n+12)=(3n+18)

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Solution for (2n+12)=(3n+18) equation: 



(2n+12)=(3n+18)

We move all terms to the left:

(2n+12)-((3n+18))=0

We get rid of parentheses

2n-((3n+18))+12=0



We calculate terms in parentheses: -((3n+18)), so:

(3n+18)

We get rid of parentheses

3n+18

Back to the equation:

-(3n+18)



We get rid of parentheses

2n-3n-18+12=0

We add all the numbers together, and all the variables

-1n-6=0

We move all terms containing n to the left, all other terms to the right

-n=6

n=6/-1

n=-6

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