(2n+2)(2n-2)=

Solution for (2n+2)(2n-2)= equation:

Simplifying
(2n + 2)(2n + -2) = 0

Reorder the terms:
(2 + 2n)(2n + -2) = 0

Reorder the terms:
(2 + 2n)(-2 + 2n) = 0

Multiply (2 + 2n) * (-2 + 2n)
(2(-2 + 2n) + 2n * (-2 + 2n)) = 0
((-2 * 2 + 2n * 2) + 2n * (-2 + 2n)) = 0
((-4 + 4n) + 2n * (-2 + 2n)) = 0
(-4 + 4n + (-2 * 2n + 2n * 2n)) = 0
(-4 + 4n + (-4n + 4n2)) = 0

Combine like terms: 4n + -4n = 0
(-4 + 0 + 4n2) = 0
(-4 + 4n2) = 0

Solving
-4 + 4n2 = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4n2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 4n2 = 0 + 4
4n2 = 0 + 4

Combine like terms: 0 + 4 = 4
4n2 = 4

Divide each side by '4'.
n2 = 1

Simplifying
n2 = 1

Take the square root of each side:
n = {-1, 1}