(2n+2)(6n)=

Solution for (2n+2)(6n)= equation:

(2n+2)(6n)=

We move all terms to the left:

(2n+2)(6n)-()=0

We add all the numbers together, and all the variables

(2n+2)6n=0

We multiply parentheses

12n^2+12n=0

a = 12; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·12·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*12}=\frac{-24}{24}
=-1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*12}=\frac{0}{24}
=0
$