(2n+2)3=4(n+4)

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Solution for (2n+2)3=4(n+4) equation: 



(2n+2)3=4(n+4)

We move all terms to the left:

(2n+2)3-(4(n+4))=0

We multiply parentheses

6n-(4(n+4))+6=0



We calculate terms in parentheses: -(4(n+4)), so:

4(n+4)

We multiply parentheses

4n+16

Back to the equation:

-(4n+16)



We get rid of parentheses

6n-4n-16+6=0

We add all the numbers together, and all the variables

2n-10=0

We move all terms containing n to the left, all other terms to the right

2n=10

n=10/2

n=5

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