(2n+3)/3=(4n-10)/2

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Solution for (2n+3)/3=(4n-10)/2 equation: 



(2n+3)/3=(4n-10)/2

We move all terms to the left:

(2n+3)/3-((4n-10)/2)=0

We calculate fractions


2n/()+(-((4n-10)*3)/()=0



We calculate terms in parentheses: +(-((4n-10)*3)/(), so:

-((4n-10)*3)/(

We multiply all the terms by the denominator


-((4n-10)*3)



We calculate terms in parentheses: -((4n-10)*3), so:

(4n-10)*3

We multiply parentheses

12n-30

Back to the equation:

-(12n-30)



We get rid of parentheses

-12n+30

Back to the equation:

+(-12n+30)



We get rid of parentheses

2n/()-12n+30=0

We multiply all the terms by the denominator


2n-12n*()+30*()=0

We add all the numbers together, and all the variables

2n-12n*()=0

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