(2n+3/4)=(5n-1)/6

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Solution for (2n+3/4)=(5n-1)/6 equation: 



(2n+3/4)=(5n-1)/6

We move all terms to the left:

(2n+3/4)-((5n-1)/6)=0

We add all the numbers together, and all the variables

(+2n+3/4)-((5n-1)/6)=0

We get rid of parentheses

2n-((5n-1)/6)+3/4=0

We calculate fractions


2n+(-((5n-1)*4)/()+()/()=0



We calculate terms in parentheses: +(-((5n-1)*4)/()+()/(), so:

-((5n-1)*4)/()+()/(

We add all the numbers together, and all the variables

-((5n-1)*4)/()+1

We multiply all the terms by the denominator


-((5n-1)*4)+1*()



We calculate terms in parentheses: -((5n-1)*4), so:

(5n-1)*4

We multiply parentheses

20n-4

Back to the equation:

-(20n-4)



We add all the numbers together, and all the variables

-(20n-4)

We get rid of parentheses

-20n+4

Back to the equation:

+(-20n+4)



We get rid of parentheses

2n-20n+4=0

We add all the numbers together, and all the variables

-18n+4=0

We move all terms containing n to the left, all other terms to the right

-18n=-4

n=-4/-18

n=2/9

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