(2n+4)(n-2)=

Solution for (2n+4)(n-2)= equation:

Simplifying
(2n + 4)(n + -2) = 0

Reorder the terms:
(4 + 2n)(n + -2) = 0

Reorder the terms:
(4 + 2n)(-2 + n) = 0

Multiply (4 + 2n) * (-2 + n)
(4(-2 + n) + 2n * (-2 + n)) = 0
((-2 * 4 + n * 4) + 2n * (-2 + n)) = 0
((-8 + 4n) + 2n * (-2 + n)) = 0
(-8 + 4n + (-2 * 2n + n * 2n)) = 0
(-8 + 4n + (-4n + 2n2)) = 0

Combine like terms: 4n + -4n = 0
(-8 + 0 + 2n2) = 0
(-8 + 2n2) = 0

Solving
-8 + 2n2 = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2n2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2n2 = 0 + 8
2n2 = 0 + 8

Combine like terms: 0 + 8 = 8
2n2 = 8

Divide each side by '2'.
n2 = 4

Simplifying
n2 = 4

Take the square root of each side:
n = {-2, 2}