(2n+4)+(n-2)=

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Solution for (2n+4)+(n-2)= equation: 



(2n+4)+(n-2)=

We move all terms to the left:

(2n+4)+(n-2)-()=0

We add all the numbers together, and all the variables

(2n+4)+(n-2)=0

We get rid of parentheses

2n+n+4-2=0

We add all the numbers together, and all the variables

3n+2=0

We move all terms containing n to the left, all other terms to the right

3n=-2

n=-2/3

n=-2/3

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