(2n+4)+(n-3)=3n+1

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Solution for (2n+4)+(n-3)=3n+1 equation:


Simplifying
(2n + 4) + (n + -3) = 3n + 1

Reorder the terms:
(4 + 2n) + (n + -3) = 3n + 1

Remove parenthesis around (4 + 2n)
4 + 2n + (n + -3) = 3n + 1

Reorder the terms:
4 + 2n + (-3 + n) = 3n + 1

Remove parenthesis around (-3 + n)
4 + 2n + -3 + n = 3n + 1

Reorder the terms:
4 + -3 + 2n + n = 3n + 1

Combine like terms: 4 + -3 = 1
1 + 2n + n = 3n + 1

Combine like terms: 2n + n = 3n
1 + 3n = 3n + 1

Reorder the terms:
1 + 3n = 1 + 3n

Add '-1' to each side of the equation.
1 + -1 + 3n = 1 + -1 + 3n

Combine like terms: 1 + -1 = 0
0 + 3n = 1 + -1 + 3n
3n = 1 + -1 + 3n

Combine like terms: 1 + -1 = 0
3n = 0 + 3n
3n = 3n

Add '-3n' to each side of the equation.
3n + -3n = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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