(2n+6)/3=((9n-4)/5)-n

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Solution for (2n+6)/3=((9n-4)/5)-n equation: 


n in (-oo:+oo)

(2*n+6)/3 = (9*n-4)/5-n // - (9*n-4)/5-n

(2*n+6)/3-((9*n-4)/5)+n = 0

(2*n+6)/3+(-1*(9*n-4))/5+n = 0

(5*(2*n+6))/(3*5)+(-1*3*(9*n-4))/(3*5)+(3*5*n)/(3*5) = 0

5*(2*n+6)-1*3*(9*n-4)+3*5*n = 0

15*n-17*n+42 = 0

42-2*n = 0

(42-2*n)/(3*5) = 0

(42-2*n)/(3*5) = 0 // * 3*5

42-2*n = 0

42-2*n = 0 // - 42

-2*n = -42 // : -2

n = -42/(-2)

n = 21

n = 21

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