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(2n+7)(7n-6)=0
We multiply parentheses ..
(+14n^2-12n+49n-42)=0
We get rid of parentheses
14n^2-12n+49n-42=0
We add all the numbers together, and all the variables
14n^2+37n-42=0
a = 14; b = 37; c = -42;
Δ = b2-4ac
Δ = 372-4·14·(-42)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-61}{2*14}=\frac{-98}{28} =-3+1/2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+61}{2*14}=\frac{24}{28} =6/7 $
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