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(2n-1)(5n+6)=0
We multiply parentheses ..
(+10n^2+12n-5n-6)=0
We get rid of parentheses
10n^2+12n-5n-6=0
We add all the numbers together, and all the variables
10n^2+7n-6=0
a = 10; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·10·(-6)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*10}=\frac{-24}{20} =-1+1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*10}=\frac{10}{20} =1/2 $
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