(2n-2)(n+1)=0

Solution for (2n-2)(n+1)=0 equation:

Simplifying
(2n + -2)(n + 1) = 0

Reorder the terms:
(-2 + 2n)(n + 1) = 0

Reorder the terms:
(-2 + 2n)(1 + n) = 0

Multiply (-2 + 2n) * (1 + n)
(-2(1 + n) + 2n * (1 + n)) = 0
((1 * -2 + n * -2) + 2n * (1 + n)) = 0
((-2 + -2n) + 2n * (1 + n)) = 0
(-2 + -2n + (1 * 2n + n * 2n)) = 0
(-2 + -2n + (2n + 2n2)) = 0

Combine like terms: -2n + 2n = 0
(-2 + 0 + 2n2) = 0
(-2 + 2n2) = 0

Solving
-2 + 2n2 = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 2n2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 2n2 = 0 + 2
2n2 = 0 + 2

Combine like terms: 0 + 2 = 2
2n2 = 2

Divide each side by '2'.
n2 = 1

Simplifying
n2 = 1

Take the square root of each side:
n = {-1, 1}