(2n-3)+(n+4)=

Solution for (2n-3)+(n+4)= equation:

Simplifying
(2n + -3) + (n + 4) = 0

Reorder the terms:
(-3 + 2n) + (n + 4) = 0

Remove parenthesis around (-3 + 2n)
-3 + 2n + (n + 4) = 0

Reorder the terms:
-3 + 2n + (4 + n) = 0

Remove parenthesis around (4 + n)
-3 + 2n + 4 + n = 0

Reorder the terms:
-3 + 4 + 2n + n = 0

Combine like terms: -3 + 4 = 1
1 + 2n + n = 0

Combine like terms: 2n + n = 3n
1 + 3n = 0

Solving
1 + 3n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 3n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 3n = 0 + -1
3n = 0 + -1

Combine like terms: 0 + -1 = -1
3n = -1

Divide each side by '3'.
n = -0.3333333333

Simplifying
n = -0.3333333333