(2n-3)/(5)=(n+1)/(4)

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Solution for (2n-3)/(5)=(n+1)/(4) equation: 



(2n-3)/(5)=(n+1)/(4)

We move all terms to the left:

(2n-3)/(5)-((n+1)/(4))=0

We calculate fractions


2n/()+(-((n+1)*5)/()=0



We calculate terms in parentheses: +(-((n+1)*5)/(), so:

-((n+1)*5)/(

We multiply all the terms by the denominator


-((n+1)*5)



We calculate terms in parentheses: -((n+1)*5), so:

(n+1)*5

We multiply parentheses

5n+5

Back to the equation:

-(5n+5)



We get rid of parentheses

-5n-5

Back to the equation:

+(-5n-5)



We get rid of parentheses

2n/()-5n-5=0

We multiply all the terms by the denominator


2n-5n*()-5*()=0

We add all the numbers together, and all the variables

2n-5n*()=0

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