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(2n-5)(n-5)=(2n-7)(n-3)
We move all terms to the left:
(2n-5)(n-5)-((2n-7)(n-3))=0
We multiply parentheses ..
(+2n^2-10n-5n+25)-((2n-7)(n-3))=0
We calculate terms in parentheses: -((2n-7)(n-3)), so:We get rid of parentheses
(2n-7)(n-3)
We multiply parentheses ..
(+2n^2-6n-7n+21)
We get rid of parentheses
2n^2-6n-7n+21
We add all the numbers together, and all the variables
2n^2-13n+21
Back to the equation:
-(2n^2-13n+21)
2n^2-2n^2-10n-5n+13n+25-21=0
We add all the numbers together, and all the variables
-2n+4=0
We move all terms containing n to the left, all other terms to the right
-2n=-4
n=-4/-2
n=+2
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