(2n-5)(n-5)=(2n-7)(n-3)

Solution for (2n-5)(n-5)=(2n-7)(n-3) equation:

(2n-5)(n-5)=(2n-7)(n-3)

We move all terms to the left:

(2n-5)(n-5)-((2n-7)(n-3))=0

We multiply parentheses ..

(+2n^2-10n-5n+25)-((2n-7)(n-3))=0


We calculate terms in parentheses: -((2n-7)(n-3)), so:

(2n-7)(n-3)

We multiply parentheses ..

(+2n^2-6n-7n+21)

We get rid of parentheses

2n^2-6n-7n+21

We add all the numbers together, and all the variables

2n^2-13n+21

Back to the equation:

-(2n^2-13n+21)


We get rid of parentheses

2n^2-2n^2-10n-5n+13n+25-21=0

We add all the numbers together, and all the variables

-2n+4=0

We move all terms containing n to the left, all other terms to the right

-2n=-4

n=-4/-2

n=+2