(2p+4)(4p+2)=0

Solution for (2p+4)(4p+2)=0 equation:

(2p+4)(4p+2)=0

We multiply parentheses ..

(+8p^2+4p+16p+8)=0

We get rid of parentheses

8p^2+4p+16p+8=0

We add all the numbers together, and all the variables

8p^2+20p+8=0

a = 8; b = 20; c = +8;
Δ = b2-4ac
Δ = 202-4·8·8
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12}{2*8}=\frac{-32}{16}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12}{2*8}=\frac{-8}{16}
=-1/2
$