(2p-2)+2=(2/3p)+6

Solution for (2p-2)+2=(2/3p)+6 equation:

(2p-2)+2=(2/3p)+6

We move all terms to the left:

(2p-2)+2-((2/3p)+6)=0


Domain of the equation: 3p)+6)!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(2p-2)-((+2/3p)+6)+2=0

We get rid of parentheses

2p-((+2/3p)+6)-2+2=0

We multiply all the terms by the denominator


2p*3p)+6)-((-2*3p)+6)+2*3p)+6)+2=0

Wy multiply elements

6p^2-18p^2=0

We add all the numbers together, and all the variables

-12p^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{-24}=0$