(2p-4)(2p-2)+6p-3=4p2-(3p-1)

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Solution for (2p-4)(2p-2)+6p-3=4p2-(3p-1) equation: 



(2p-4)(2p-2)+6p-3=4p^2-(3p-1)

We move all terms to the left:

(2p-4)(2p-2)+6p-3-(4p^2-(3p-1))=0

We add all the numbers together, and all the variables

6p+(2p-4)(2p-2)-(4p^2-(3p-1))-3=0

We multiply parentheses ..

(+4p^2-4p-8p+8)+6p-(4p^2-(3p-1))-3=0



We calculate terms in parentheses: -(4p^2-(3p-1)), so:

4p^2-(3p-1)

We get rid of parentheses

4p^2-3p+1

Back to the equation:

-(4p^2-3p+1)



We get rid of parentheses

4p^2-4p^2-4p-8p+6p+3p+8-1-3=0

We add all the numbers together, and all the variables

-3p+4=0

We move all terms containing p to the left, all other terms to the right

-3p=-4

p=-4/-3

p=1+1/3

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