(2q-1)(q-3)=

Solution for (2q-1)(q-3)= equation:

Simplifying
(2q + -1)(q + -3) = 0

Reorder the terms:
(-1 + 2q)(q + -3) = 0

Reorder the terms:
(-1 + 2q)(-3 + q) = 0

Multiply (-1 + 2q) * (-3 + q)
(-1(-3 + q) + 2q * (-3 + q)) = 0
((-3 * -1 + q * -1) + 2q * (-3 + q)) = 0
((3 + -1q) + 2q * (-3 + q)) = 0
(3 + -1q + (-3 * 2q + q * 2q)) = 0
(3 + -1q + (-6q + 2q2)) = 0

Combine like terms: -1q + -6q = -7q
(3 + -7q + 2q2) = 0

Solving
3 + -7q + 2q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(1 + -2q)(3 + -1q) = 0

Subproblem 1
Set the factor '(1 + -2q)' equal to zero and attempt to solve:

Simplifying
1 + -2q = 0

Solving
1 + -2q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2q = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2q = 0 + -1
-2q = 0 + -1

Combine like terms: 0 + -1 = -1
-2q = -1

Divide each side by '-2'.
q = 0.5

Simplifying
q = 0.5
Subproblem 2
Set the factor '(3 + -1q)' equal to zero and attempt to solve:

Simplifying
3 + -1q = 0

Solving
3 + -1q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1q = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1q = 0 + -3
-1q = 0 + -3

Combine like terms: 0 + -3 = -3
-1q = -3

Divide each side by '-1'.
q = 3

Simplifying
q = 3
Solution
q = {0.5, 3}