(2q-3)q=27

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Solution for (2q-3)q=27 equation:


Simplifying
(2q + -3) * q = 27

Reorder the terms:
(-3 + 2q) * q = 27

Reorder the terms for easier multiplication:
q(-3 + 2q) = 27
(-3 * q + 2q * q) = 27
(-3q + 2q2) = 27

Solving
-3q + 2q2 = 27

Solving for variable 'q'.

Reorder the terms:
-27 + -3q + 2q2 = 27 + -27

Combine like terms: 27 + -27 = 0
-27 + -3q + 2q2 = 0

Factor a trinomial.
(-3 + -1q)(9 + -2q) = 0

Subproblem 1

Set the factor '(-3 + -1q)' equal to zero and attempt to solve: Simplifying -3 + -1q = 0 Solving -3 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1q = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1q = 0 + 3 -1q = 0 + 3 Combine like terms: 0 + 3 = 3 -1q = 3 Divide each side by '-1'. q = -3 Simplifying q = -3

Subproblem 2

Set the factor '(9 + -2q)' equal to zero and attempt to solve: Simplifying 9 + -2q = 0 Solving 9 + -2q = 0 Move all terms containing q to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + -2q = 0 + -9 Combine like terms: 9 + -9 = 0 0 + -2q = 0 + -9 -2q = 0 + -9 Combine like terms: 0 + -9 = -9 -2q = -9 Divide each side by '-2'. q = 4.5 Simplifying q = 4.5

Solution

q = {-3, 4.5}

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