(2r+12)/8=(2r-12)/2

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Solution for (2r+12)/8=(2r-12)/2 equation:



(2r+12)/8=(2r-12)/2
We move all terms to the left:
(2r+12)/8-((2r-12)/2)=0
We calculate fractions
2r/()+(-((2r-12)*8)/()=0
We calculate terms in parentheses: +(-((2r-12)*8)/(), so:
-((2r-12)*8)/(
We multiply all the terms by the denominator
-((2r-12)*8)
We calculate terms in parentheses: -((2r-12)*8), so:
(2r-12)*8
We multiply parentheses
16r-96
Back to the equation:
-(16r-96)
We get rid of parentheses
-16r+96
Back to the equation:
+(-16r+96)
We get rid of parentheses
2r/()-16r+96=0
We multiply all the terms by the denominator
2r-16r*()+96*()=0
We add all the numbers together, and all the variables
2r-16r*()=0

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