(2r+12)/8=(4r-12)/4

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Solution for (2r+12)/8=(4r-12)/4 equation:



(2r+12)/8=(4r-12)/4
We move all terms to the left:
(2r+12)/8-((4r-12)/4)=0
We calculate fractions
2r/()+(-((4r-12)*8)/()=0
We calculate terms in parentheses: +(-((4r-12)*8)/(), so:
-((4r-12)*8)/(
We multiply all the terms by the denominator
-((4r-12)*8)
We calculate terms in parentheses: -((4r-12)*8), so:
(4r-12)*8
We multiply parentheses
32r-96
Back to the equation:
-(32r-96)
We get rid of parentheses
-32r+96
Back to the equation:
+(-32r+96)
We get rid of parentheses
2r/()-32r+96=0
We multiply all the terms by the denominator
2r-32r*()+96*()=0
We add all the numbers together, and all the variables
2r-32r*()=0

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