(2r+3)/(3r-6)=6

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Solution for (2r+3)/(3r-6)=6 equation:



(2r+3)/(3r-6)=6
We move all terms to the left:
(2r+3)/(3r-6)-(6)=0
Domain of the equation: (3r-6)!=0
We move all terms containing r to the left, all other terms to the right
3r!=6
r!=6/3
r!=2
r∈R
We multiply all the terms by the denominator
(2r+3)-6*(3r-6)=0
We multiply parentheses
(2r+3)-18r+36=0
We get rid of parentheses
2r-18r+3+36=0
We add all the numbers together, and all the variables
-16r+39=0
We move all terms containing r to the left, all other terms to the right
-16r=-39
r=-39/-16
r=2+7/16

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