(2r+5t)(2r-5t)=

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Solution for (2r+5t)(2r-5t)= equation:


Simplifying
(2r + 5t)(2r + -5t) = 0

Multiply (2r + 5t) * (2r + -5t)
(2r * (2r + -5t) + 5t * (2r + -5t)) = 0
((2r * 2r + -5t * 2r) + 5t * (2r + -5t)) = 0

Reorder the terms:
((-10rt + 4r2) + 5t * (2r + -5t)) = 0
((-10rt + 4r2) + 5t * (2r + -5t)) = 0
(-10rt + 4r2 + (2r * 5t + -5t * 5t)) = 0
(-10rt + 4r2 + (10rt + -25t2)) = 0

Reorder the terms:
(-10rt + 10rt + 4r2 + -25t2) = 0

Combine like terms: -10rt + 10rt = 0
(0 + 4r2 + -25t2) = 0
(4r2 + -25t2) = 0

Solving
4r2 + -25t2 = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '25t2' to each side of the equation.
4r2 + -25t2 + 25t2 = 0 + 25t2

Combine like terms: -25t2 + 25t2 = 0
4r2 + 0 = 0 + 25t2
4r2 = 0 + 25t2
Remove the zero:
4r2 = 25t2

Divide each side by '4'.
r2 = 6.25t2

Simplifying
r2 = 6.25t2

Take the square root of each side:
r = {-2.5t, 2.5t}

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