(2r+6)/6=(4r-1)/15

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Solution for (2r+6)/6=(4r-1)/15 equation: 



(2r+6)/6=(4r-1)/15

We move all terms to the left:

(2r+6)/6-((4r-1)/15)=0

We calculate fractions


2r/()+(-((4r-1)*6)/()=0



We calculate terms in parentheses: +(-((4r-1)*6)/(), so:

-((4r-1)*6)/(

We multiply all the terms by the denominator


-((4r-1)*6)



We calculate terms in parentheses: -((4r-1)*6), so:

(4r-1)*6

We multiply parentheses

24r-6

Back to the equation:

-(24r-6)



We get rid of parentheses

-24r+6

Back to the equation:

+(-24r+6)



We get rid of parentheses

2r/()-24r+6=0

We multiply all the terms by the denominator


2r-24r*()+6*()=0

We add all the numbers together, and all the variables

2r-24r*()=0

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