(2r+6)/8=(2r-1)/7

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Solution for (2r+6)/8=(2r-1)/7 equation: 



(2r+6)/8=(2r-1)/7

We move all terms to the left:

(2r+6)/8-((2r-1)/7)=0

We calculate fractions


2r/()+(-((2r-1)*8)/()=0



We calculate terms in parentheses: +(-((2r-1)*8)/(), so:

-((2r-1)*8)/(

We multiply all the terms by the denominator


-((2r-1)*8)



We calculate terms in parentheses: -((2r-1)*8), so:

(2r-1)*8

We multiply parentheses

16r-8

Back to the equation:

-(16r-8)



We get rid of parentheses

-16r+8

Back to the equation:

+(-16r+8)



We get rid of parentheses

2r/()-16r+8=0

We multiply all the terms by the denominator


2r-16r*()+8*()=0

We add all the numbers together, and all the variables

2r-16r*()=0

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