(2r+7)/5r=5/3

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Solution for (2r+7)/5r=5/3 equation: 



(2r+7)/5r=5/3

We move all terms to the left:

(2r+7)/5r-(5/3)=0



Domain of the equation: 5r!=0

r!=0/5

r!=0

r∈R



We add all the numbers together, and all the variables

(2r+7)/5r-(+5/3)=0

We get rid of parentheses

(2r+7)/5r-5/3=0

We calculate fractions


(6r+21)/15r+(-25r)/15r=0

We multiply all the terms by the denominator


(6r+21)+(-25r)=0

We get rid of parentheses

6r-25r+21=0

We add all the numbers together, and all the variables

-19r+21=0

We move all terms containing r to the left, all other terms to the right

-19r=-21

r=-21/-19

r=1+2/19

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