(2r-2)+(3r-3)=90

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Solution for (2r-2)+(3r-3)=90 equation: 



(2r-2)+(3r-3)=90

We move all terms to the left:

(2r-2)+(3r-3)-(90)=0

We get rid of parentheses

2r+3r-2-3-90=0

We add all the numbers together, and all the variables

5r-95=0

We move all terms containing r to the left, all other terms to the right

5r=95

r=95/5

r=19

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