(2r-2)+(3r-3)=90

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Solution for (2r-2)+(3r-3)=90 equation:



(2r-2)+(3r-3)=90
We move all terms to the left:
(2r-2)+(3r-3)-(90)=0
We get rid of parentheses
2r+3r-2-3-90=0
We add all the numbers together, and all the variables
5r-95=0
We move all terms containing r to the left, all other terms to the right
5r=95
r=95/5
r=19

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