(2r-20)+(2r-20)=3r+10

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Solution for (2r-20)+(2r-20)=3r+10 equation: 



(2r-20)+(2r-20)=3r+10

We move all terms to the left:

(2r-20)+(2r-20)-(3r+10)=0

We get rid of parentheses

2r+2r-3r-20-20-10=0

We add all the numbers together, and all the variables

r-50=0

We move all terms containing r to the left, all other terms to the right

r=50

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