(2r-3)/7+(3/7)=(-r/3)

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Solution for (2r-3)/7+(3/7)=(-r/3) equation: 


r in (-oo:+oo)

(2*r-3)/7+3/7 = -r/3 // + -r/3

(2*r-3)/7-(-r/3)+3/7 = 0

(2*r-3)/7+(1/3)*r+3/7 = 0

(2*r-3)/7+r/3+3/7 = 0

(3*(2*r-3))/(3*7)+(7*r)/(3*7)+(3^2)/(3*7) = 0

3*(2*r-3)+7*r+9 = 0

13*r-9+9 = 0

13*r = 0

(13*r)/(3*7) = 0

(13*r)/(3*7) = 0 // * 3*7

13*r = 0

13*r = 0 // : 13

r = 0

r = 0

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