(2r-4)(2r+4)=

Solution for (2r-4)(2r+4)= equation:

Simplifying
(2r + -4)(2r + 4) = 0

Reorder the terms:
(-4 + 2r)(2r + 4) = 0

Reorder the terms:
(-4 + 2r)(4 + 2r) = 0

Multiply (-4 + 2r) * (4 + 2r)
(-4(4 + 2r) + 2r * (4 + 2r)) = 0
((4 * -4 + 2r * -4) + 2r * (4 + 2r)) = 0
((-16 + -8r) + 2r * (4 + 2r)) = 0
(-16 + -8r + (4 * 2r + 2r * 2r)) = 0
(-16 + -8r + (8r + 4r2)) = 0

Combine like terms: -8r + 8r = 0
(-16 + 0 + 4r2) = 0
(-16 + 4r2) = 0

Solving
-16 + 4r2 = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4r2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4r2 = 0 + 16
4r2 = 0 + 16

Combine like terms: 0 + 16 = 16
4r2 = 16

Divide each side by '4'.
r2 = 4

Simplifying
r2 = 4

Take the square root of each side:
r = {-2, 2}