(2r/3)-7=r+5

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Solution for (2r/3)-7=r+5 equation: 



(2r/3)-7=r+5

We move all terms to the left:

(2r/3)-7-(r+5)=0

We add all the numbers together, and all the variables

(+2r/3)-(r+5)-7=0

We get rid of parentheses

2r/3-r-5-7=0

We multiply all the terms by the denominator


2r-r*3-5*3-7*3=0

We add all the numbers together, and all the variables

2r-r*3-36=0

Wy multiply elements

2r-3r-36=0

We add all the numbers together, and all the variables

-1r-36=0

We move all terms containing r to the left, all other terms to the right

-r=36

r=36/-1

r=-36

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